Description on explicit and implicit analysis
When we applied a load it was applied in steps. And we apply load in steps in implicit type of analysis .This phenomenon / approach is called as incremental approach . Now Implicit and explicit solver both apply this approach . Where they apply load in steps.
The only difference between this two solver is that implicit ,uses an iterative approach along with the incremental method.
The implicit solver try’s to achieve the equilibrium between the internal and external forces  at each steps ,within that particular model, only then it will progressed to the next step.(force convergence graph)
But, for explicit solver it doesn’t try to achieve equilibrium at each step. If there are unbalanced forces these unbalanced forces are multiplied with step and we get wrong answer.
Here we have to specify a lowest time step
Also the research provides that data that the implicit solver is not suitable / less accurate for simulation stress wave propagation events,(drop event,car crash event).
Implicit solver only handle the static problem accurately.

Explicit calculation
Consider a  case of simple bar in tension .suppose that the force in the bar is a non-linear function of displacement .
F(u) = u3 +u2+4u     -------------1
From1 it follows that the stifness of the bar is
K(u)=df/dx = 3u2+2u+4---------------2
∆F=K *∆u
|                                                               u                                       F
|

Step1
 u0 = 0.0                      K(u0) =4                 ∆F=1            ∆u1 =∆F/K(u0) = ¼ 
therefore, u1=u0+∆u1 = 0+1/4 =0.25
Step2
K(u1) =3*(1/4)2+2*1/2+4 =4.6875               ∆F=1            ∆u2 =∆F/K(u1) =0.2133
therefore, u2=u1+∆u2 = 0.25+0.2133=0.4633
Step3
K(u2) =3*(0.4633)2+2*0.4633+4 =5.5704             ∆F=1            ∆u3 =∆F/K(u2) =1/5.5704=0.1795
therefore, u3=u2+∆u3 =0.4633+0.1795=0.6383
Step i
∆Fi
∆ui
ui
(Fext)i
(Fint)i
Fint-Fext=R
1
1
0.25
0.25
1
1.0781
0.0781
2
1
0.2133
0.4633
2
2.1672
0.1672
3
1
0.1795
0.6383
3
3.2206
0.2206





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